Ideal gas law problems solutions

The molecules to come close to each other for the liquefaction of gas molecules. The intermolecular attraction needed for the liquefaction of gas.

An ideal gas has no intermolecular attraction and hence ideal gas can not be liquefied.

Further putting the condition of the critical state to the ideal gas law.

PV = RT

At the critical state

∴ - RTc/Vc² = 0

or, Tc = 0⁰ K

Thus for liquefying an ideal gas necessary to bring the temperature below 0⁰ K. Naturally this temperature not possible thus the gas can not be liquefied.

Total kinetic energy

∴ E_total = 1702 Joule

Where M = molecular weight of the gas

=31.91 gm mol^-1

Molecular weight of ammonia = 17 gm mol^-1

P = 1600 mm Hg = 1600/760 atm

R = 82.1 cc atm mol^-1 K^-1

T = (273 +100) K

Thus the density of ammonia = 0.00117 gm/cc

PV = nRT

The molecular weight of nitrogen 28 gm mol^-1

= 2.05 atm