## What is entropy in thermodynamics?

Entropy in chemistry is the thermodynamics property related to the tendency of the system towards the transformation of the states of matter. It measures the thermal energy of the system per unit temperature that is unavailable for doing useful work. When a substance changes its phase from solid to liquid to gases, the entropy increases from solid to liquid to gases. From the molecular viewpoint, we see that randomness of the molecules increases from solid to liquid to gases. In learning chemistry, entropy (S) is the property that measures the randomness or chaotic condition of the system.

### Examples of entropy change

For example, if we lose a quantity of yellowish green chlorine gas at the corner of the room. The gas speared in all directions of the room until the equilibrium or maximum entropy was reached. A similar process happens when syrup gets diluted by adding water. Moreover, all the natural processes in our environment have a tendency to attain equilibrium by increasing the entropy of the system.

### Significance of entropy

The concept of entropy is obtained from the unavailable energy in thermodynamics. The higher the randomness greater will be the entropy for molecules. A system passes spontaneously from more orderliness to less orderliness. If the system is left to change its state spontaneously, it attains a maximum chaotic state. Therefore, for a spontaneous process, the Î”S_{net} of the universe (system + surroundings) increases. The system attains equilibrium when the Î”S_{net} is maximum.

## Thermodynamic definition of entropy

Clasusious defined entropy (S) is a state function and its change is defined as dS = dq_{r}/T, where dq_{r} = heat change that occurs reversibly and T = temperature at which heat change occurs. When heat change occurs in different temperatures, ds = dq_{1}/T_{1} + dq_{2}/T_{2} + dq_{3}/T_{3} + … = âˆ« dq_{r}/T.

- Absorption of heat increases the entropy of the system while evaluation of heat decreases the value of S.
- For reversible adiabatic process, dq = 0. Therefore, dS = 0. It means entropy remains constant for isolated systems or adiabatic processes.

### How to calculate entropy change in thermodynamics?

When one mole water heated reversibly from 27 Â°C to 37 Â°C. The entropy change, Î”S = nC_{p}ln(T_{2}/T_{1}) = 1 Ã— 18 Ã— ln(310/300) = 1.18 cal/deg.

### Entropy change at a constant temperature

When heat change occurs at a constant temperature. For example, one mole ice changes into liquid water at 0 Â°C and 1 atmosphere pressure. Therefore, entropy change (Î”S) = S_{2} -S_{1} = (18 Ã— 80)/273 cal/deg = 5.27 cal/deg.

## Entropy change of the universe

In a reversible process, heat absorbed by the system is equal to that lost from the surroundings. Let dq_{r} amount of heat is absorbed by the system and -dq_{r} heat lost from the surroundings at temperature T. Therefore, Î”S_{system} = dqr/T and Î”S_{surrounding} = -dqr/T. From these two equations, the entropy change of the universe (Î”Sunivese) = Î”S_{system} + Î”S_{surrounding} = 0.

### Thermodynamic equation

The 1st law of thermodynamics for a reversible process, dq_{r} = dU + PdV. From the 2nd law, dS = dq_{r}/T or TdS = PdV. Combining both the forms, we have the relation TdS = dU + PdV. Again dH = U + PV or dH = dU + PdV + VdP. Therefore, dH = TdS + VdP. These two equations are called basic thermodynamic equations for states.

## Work done in Carnot Cycle

French engineer Sadi Carnot (1824) study what quantity of work is obtainable from the heat in the Carnot engine. He takes the ideal gas in a cylinder fitted with a frictionless movable piston. The Carnot cycle operates in reversible paths given above the picture. From Carnot cycles, we can conclude that heat change/temperature = constant for the change of two definite states and independent of path change. For the whole cycle of operation, heat change/temperature is equal to zero.

## Unavailable energy and entropy

From the Carnot cycles, dq_{1}/T_{1} = dq_{2}/T_{2}, where dq_{1} = energy supplied to the Carnot cycle at temperature T_{1}. But the Carnot cycle fails to convert dq_{2} heat into useful work. It is rejected from the sink at T_{2}. Therefore, the unavailable energy for the cycle = dq_{2}. The unavailable energy for the Carnot cycle = T_{2}dS

When a system absorbed a certain amount of heat in the reversible process, a part of absorbed energy can utilize for producing work. The remaining part goes to increases the randomness orÂ entropy of the system.